यदि mathop {lim }limits_{x to 0} phi (x) = {a | vedclass

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(B) माना $t = \frac{x}{a}$। जैसे $x 	o 0$,वैसे $t 	o 0$ क्योंकि $a 
e 0$ है।अतः,$\mathop {\lim }\limits_{x 	o 0} \phi \left( {\frac{x}{a}} ight)

Vedclass · Accepted Answer

$a^3$

Vedclass · Answer

(B) माना $t = \frac{x}{a}$। जैसे $x 	o 0$,वैसे $t 	o 0$ क्योंकि $a 
e 0$ है।अतः,$\mathop {\lim }\limits_{x 	o 0} \phi \left( {\frac{x}{a}} ight) = \mathop {\lim }\limits_{t 	o 0} \phi (t)$।चूंकि $\mathop {\lim }\limits_{x 	o 0} \phi (x) = a^3$,इसलिए $\mathop {\lim }\limits_{t 	o 0} \phi (t) = a^3$ होगा।अतः,सीमा का मान $a^3$ है।

यदि $\mathop {\lim }\limits_{x \to 0} \phi (x) = {a^3}, (a \ne 0)$; तो $\mathop {\lim }\limits_{x \to 0} \phi \left( {\frac{x}{a}} \right)$ का मान ज्ञात कीजिए :-

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